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✨ Add ListExtensions.Shuffle<T>()
Shuffle<T>() returns the source enumerable ordered randomly
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/// <returns>Returns a random element of type <see cref="T"/> from <paramref name="source"/>.</returns>
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public static T OneOf<T>(this IList<T> source, Random random) =>
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random.OneOf(source);
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/// <summary>
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/// Shuffles an enumerable.
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/// </summary>
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/// <typeparam name="T">The collection type.</typeparam>
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/// <param name="source">The collection to shuffle.</param>
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/// <returns>Returns <paramref name="source"/> shuffled.</returns>
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public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> source) =>
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source.Shuffle(new Random());
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/// <summary>
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/// Shuffles an enumerable.
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/// </summary>
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/// <typeparam name="T">The collection type.</typeparam>
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/// <param name="source">The collection to shuffle.</param>
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/// <param name="random">The <see cref="Random"/> instance.</param>
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/// <returns>Returns <paramref name="source"/> shuffled.</returns>
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public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> source, Random random) =>
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source.OrderBy(x => random.Next());
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}
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}
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