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Code Issues

Add Random.Next<T>() where T : Enum

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This commit is contained in:
Oliver Booth 2021-03-07 14:20:01 +00:00
parent fc96840e9d
commit a401aabee8
1 changed files with 21 additions and 0 deletions
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21
X10D/src/RandomExtensions/RandomExtensions.cs
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@ -11,6 +11,27 @@ namespace X10D.RandomExtensions
{
internal static readonly Random Random = new();
/// <summary>
/// Returns a random value that defined in a specified enum.
/// </summary>
/// <param name="random">The <see cref="System.Random" /> instance.</param>
/// <typeparam name="T">An enum type.</typeparam>
/// <returns>
/// A <typeparamref name="T" /> value at index <c>n</c> where <c>n = </c><see cref="System.Random.Next(int)" />.
/// </returns>
/// <exception cref="ArgumentNullException"><paramref name="random" /> is <see langword="null" />.</exception>
public static T Next<T>(this Random random)
where T : struct, Enum
{
if (random is null)
{
throw new ArgumentNullException(nameof(random));
}
var values = Enum.GetValues(typeof(T));
return (T)values.GetValue(random.Next(values.Length))!;
}
/// <summary>
/// Returns either <see langword="true" /> or <see langword="false" /> based on the next generation of the current
/// <see cref="System.Random" />.